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Sort Datatable randomly

This is not possible to Sort a Datatable directly.

In order to randomize the rows in a DataTable, do the following:

1) Add a random number DataColumn to the DataTable

2) For each row, generate a random number and store it to the new column

3) Create a DataView and sort by the random number DataColumn

Test this by simple ex.

DataTable dt = GetData();
dt.Columns.Add(new DataColumn("RandomNum", Type.GetType("System.Int32")));

Random random = new Random();
for (int i = 0; i < dt.Rows.Count; i++)
dt.Rows[i]["RandNum"] = random.Next(1000);

DataView dv = new DataView(dt);
dv.Sort = "RandomNum";


LGM said...

I needed a random value in a stored procedure some time ago, and it seemed as though there was no simple solution, then while I was working with uniqueidentifiers in TSQL, I discovered that I could do a simple random number effect like this...

"Select Top 10 * from Employees order by newid();"

It works... This gives me a random selection of 10 employees...

Siva said...

Nice solution

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LouDLeSs said...

This was exactly I was looking for. Thank you!!!